Now that you have made a quality JD, it can still be tricky to evaluate the skills of your applicants when you hire React Native developers. To help you with that, we have created a pool of questions that a good React Native developer should be comfortable with.
It is important to note that the ability to answer these questions doesn't imply that you have a top quality candidate. But it definitely is a big step in that direction.
To help you navigate through these questions, we’ve categorized the interview questions in 3 parts:
A. Basic concepts: Includes all basic concepts used across languages. This section will give you an understanding of how strong their programming foundation is.
B. Advanced concepts: Includes all concepts that someone with higher expertise should know.
C. DS/Algorithm questions: To test the logical capability of the candidate.
A. Basic concepts
Coming soon!
B. Advanced concepts
Coming soon!
C. Data Structure/ Algorithm
1. Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brackets must be closed in the correct order. Note that an empty string is also considered valid.
class ValidParenthesesFunc {
func isValid(_ s: String) -> Bool {
var stc = [Character]()
for char in s {
if char == "(" || char == "[" || char == "{" {
stc.append(char)
} else if char == ")" {
guard stc.count != 0 && stc.removeLast() == "(" else {
return false
}
} else if char == "]" {
guard stc.count != 0 && stc.removeLast() == "[" else {
return false
}
} else if char == "}" {
guard stc.count != 0 && stc.removeLast() == "{" else {
return false
}
}
}
return stc.isEmpty
}
}
The above code will input 0(false).
2. Write a program to find whether a string or number is palindrome or not.
function palindrome(myString){
var removeChar = myString.replace(/[^A-Z0-9]/ig, "").toLowerCase();
var checkPalindrome = removeChar.split('').reverse().join('');
if(removeChar === checkPalindrome){
document.write("<div>"+ myString + " is a Palindrome<div>");
}else{
document.write("<div>" + myString + " is not a Palindrome <div>");
}
}
palindrome('"Oh who was it I saw, oh who?"')
palindrome('"Madam"')
palindrome('"Star Wars"')
palindrome('"7,10,7,8,9"')
The output of the above code will be:
"Oh who was it I saw, oh who?" is a Palindrome
"Madam" is a Palindrome
"Star Wars" is not a Palindrome.
"7,10,7,8,9" is not a Palindrome.
3. What will the output of the following code be?
var x = 10;
var y = 5;
var z = 3;
if (x / y / z)
document.write("hi");
else
document.write("hello");
a) hi
b) hello
c) error
d) no output
The answer is A, the floating-point division in JS returns a non zero value = 0.66 which evaluates to
true and outputs ‘hi’.
